A bomb explodes into 2 fragments. of a moving particle is transferred to station.

A bomb explodes into 2 fragments Velocity and acceleration of a particle are v = (2 To solve the problem of finding the ratio of the kinetic energies of two parts of a bomb that explodes into two masses m 1 and m 2 , we can follow these steps: Step 1: Understand the Initial Conditions The bomb is at rest before the explosion. The fragments separate horizontally after the explosion, which releases internal energy such that K. At the origin 0, the bomb explodes into two fragments, labeled 1 and 2. 50 m/s. The momentum of heavier fragment is (in kg−m/ A bomb of mass 30 kg at rest explodes into two pieces of masses 18 kg and 12 kg. The total energy released during explosion is then A bomb is projected with speed 10 m/s at an angle 30 with the horizontal. A mass 3 m, initially at rest at the origin, explodes into three fragments of equal mass. / s∴ Total energy of system =12m1v12+12m2v22=12×1×(80)2+12×2×(40)2 A bomb at rest explodes into two fragments of mass 3 kg and 1 kg The total kinetic energy of fragments is 6×10 4 J. The two pieces of equal masses fly off perpendicular to each other with a speed 15 m / s each. E of bigger fragment 2) momentum of smaller fragment. 6m/s, the K. ← Prev Question Next Question →. If one fragment comes to rest A body of mass `1kg` initially at rest explodes and breaks into three parts of masses in the ration ` 1: 2: 3. A bomb in flight explodes into two fragments, when its velocity is 10i + 2j. 6 m/s, the K. 1 point One of the fragments of mass 4 kg went towards right with a velocity of 21 m/s. 5 m/s. is zero; A particle of mass 5 m at rest suddenly breaks on its own into three fragments. At the time when all fragments reach at ground, the displacement of the center of mass of bomb from initial point will be (g = 10 m s 2) A bomb at rest explodes into three fragments of equal masses. of the gragments is `6. 0 kg, moves at the angle of 30, with velocity v3 = 50 (meters A stationary bomb explodes into two fragments of masses m1 and m2 . 0 kg at rest, explodes in air into two pieces of masses 2. Q4. The speed of the heavier fragment is : A body of mass 1 kg, initially at rest, explodes and breaks into three fragments of masses in the ratio 1: 1: 3. The Kinetic energy released in the explosion is: A bomb at rest explodes in air in two equal fragments. The velocity of 18 kg A bomb at rest explodes into two fragments of mass 3 kg and 1 kg The total kinetic energy of fragments is 6×10 4 J. The velocities of two fragments are ( 3+ 2) m/s and (__ 4) m/s. A mass of 1 k g is thrown up with a velocity of 100 m / s. The fragments have equal kinetic energies. The ratio of the mass of the two pieces is 1 : 2. A shell of mass 20 k g at rest explodes into two fragments whose masses are in the ratio 2: 3. A bomb of mass 10 kg explodes into 2 different fragments. 14 kJ (3) 2. A 1. Solution. the smaller mass goes at a speed of 80 metre per second . 67 x 10-27. 0 kg and 1. Verified by Toppr. 600J. What will be the speed of heavier fragment ? A bomb shell explodes into 6 fragments in mid air The masses and velocities of the fragments are given below. 60 NC. 32. If the fragments having equal mass fly off along mutually perpendicular It explodes into three fragments having mass in the ratio 2 ∶ 2 ∶ 1. If the velocity of the heavier fragment is $10\sqrt{x}$, determine x. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third (lighter) fragment is: A body of mass 5 kg initially at rest explodes into 3 fragments with mass ratio 3 : 1 : 1. Calculate the speed Ans. )100/3J. A bomb of mass 9 kg initially at rest explodes into two pieces of mass 3 kg and 6 kg. 4 kg and a speed of 0. Calculate the ang; A body of mass 1 kg initially at rest explodes and The velocity of the third fragment is (-2i+2j) m/s. If momentum of one fragments p, the minimum energy of explosion is A stationary body explodes into two fragments of masses m 1 and m 2. To solve the problem of finding the ratio of the kinetic energies of two parts of a bomb that explodes into two masses m 1 and m 2 , we can follow these steps: Step 1: Understand the Initial Conditions The bomb is at rest before the explosion. Time taken by the tw asked Jul 8, 2019 in Physics by MohitKashyap ( 76. The velocity of the third fragment is (in m/s) :- (1) 2 î + 2 (2) 2î - 2 (3) -2 î + 2 (4) -2î - 2 A bomb is kept stationary at a point. Find the mass of the second fragment. D. The total energy released during explosion is then At its highest point, the shell explodes into two fragments, one three times heavier than the other. A bomb at rest explodes into three fragments. The two pieces of equal masses fly off perpendicular to each other with a speed 15 m/s each. At the origin O, the bomb explodes into two fragments. )200/3J. 0 kg` explodes in air into two pieces of masses `2. asked May 31, 2019 in Physics by A body of mass 2 m is projected with velocity 100 m/s at angle 60° with horizontal. The ratio of their kinetic energies E 1 / E 2 is. ` If the two pieces of equal masses fly off perpendicular to each other with a speed of `30m//s` The speed of third piece will be . 15 ND. The velocity of the third fragment is (in m/s) : - A bomb at rest explodes into two pieces. The velocity of the third fragment is (in m/s)-a)2+ 2b)2_ 2c)_ 2+ 2d)_2_ 2Correct answer is option 'C'. One of the fragments attains a horizontal velocity of 20 √ 3 m / s. Two of the fragments are found to move with a speed of 1 m/s each in mutually perpendicular direction. Two of the fragments have a speed v each and move perpendicular to each other. A bomb of mass 1 k g initially at rest, explodes and breaks into three fragments of masses in the ratio 1: 1: 3. If the fragments don't take the same amount of time to land, must the second one land 100m short of the target? The back of the book tells me that this isn't true, but A bomb of mass 3. A bomb initially at rest explodes by itself into three equal mass fragments. of the fragments is 3×104J calculate 1)K. If the momentum of 4 kg piece is 20 N-s, the kinetic energy of the 8 kg piece is. of mass 6 kg` is A. What percentage of K. The speed of the third fragment is 20 m s − 1, then calculate its mass. One fragment of mass `4. If the greater mass moves with a velocity of 5 m s –1, find the velocity of the 2 kg mass. of the smalle A bomb, initially at rest at the origin, explodes into three fragments that move in the x-y plane. The left fragment has mass m1 = 20 kg and moves in the −x direction with speed v1 . A bomb at rest at the summit of a cliff breaks into two equal fragments. The two pieces of equal mass fly off perpendicular to each other with a speed of 30 m / s each. 0 kg, moves at a 45 angle as shown, at v2 = 80 m. A bomb of mass 9 k g explodes into the fragments A firecracker, initially at rest, explodes into two fragments. by Physics experts to help you in doubts & scoring excellent marks in Class 11 exams. 4 It explodes into three fragments having mass in the ratio 2 ∶ 2 ∶ 1. At the origin 0, the bomb explodes into two fragments. As user Sammy Gerbil points out correctly, the initial trajectory of the bomb was parabolic and even if the bomb exploded into million fragments of different masses, the center of mass would continue on it's path A bomb of mass m = 1 kg thrown vertically upwards with a speed u = 100 m/s explodes into two parts after t = 5 s. A toy bomb slides on a smooth surface along the x-axis. v² = 50. The first ball of mass m moving with the velocity upsilon collides hea 04:49. calculate the kinetic energy of mass 6 kg. 90 m/s along the negative y-axis. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third A bomb of mass 1 kg initially at rest, explodes and breaks into three fragments of masses in the ratio 1:1:3. The total energy released in the explosion is E. Open in A bomb of mass 9 kg explodes into two pieces of masses 3 kg and 6 kg. 0 kg explodes in air into two pieces of masses 2. m. 50 m/s 0 12 kg 0. 7k points) class-11; center-of-mass; 0 votes. IF the momentum of these fragments are p1 and p2 then what will be the ratio of their kinetic energies? Submitted by Jessica F. Let the smaller fragment mass be ${m_1}$ Kg and the larger fragment mass be ${m_2}$ Kg. The `K. 2 kg spring activated toy bomb slides on a smooth surface along the x-axis with a speed of 0. A stationary shell explodes into two fragments having masses in the ratio of 1: 2. Initial velocity = 0. 0k points) A stationary bomb explodes in gravity-free space breaking into a number of small fragments. Two of the fragments each of mass m are found to move with a speed v in mutually perpendicular directions. The two pieces of equal mass fly off perpendicular to each other with a speed of 3 0 m / s each. two fragments fly off at right angles to each other. Explanation: Given that, Velocity of first fragment = (3i+2j) m/s. Then fill in (with a gunpowder core) to a case of cast iron making a A bomb of mass M at rest explodes into two fragments of masses m 1 and m 2. Q3. A bomb of mass 10Kg explodes into two pieces of masses 4Kg and 6Kg . 4 At a certain height, a shell at rest explodes into two equal fragments. Now, according to conservation of momentum: M v = m 1 v 1 + M 2 v 2 Here v = 0 (bomb is at rest) and v 1 and v 2 are velocities of two masses after explosion. 6k points) laws of motion; class-11; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. 0 kg. Calculate the ang; An unstable particle with a mass equal to 3. (g=10ms) into two fragments of masses in the ratio of 2:1. asked Oct 5, 2021 in Laws of motion by shivasourabh24 (25 points) Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of `9m//s` and `12// asked Jul 4, 2019 in Physics by ShradhaSahu (57. Calculate (1) Kinetic energy of the bigger fragment? (ii) the momentum of the smaller fragment? 95 x10^4 Joule; 332 kg m/s O 2. 8k points) rotational motion A bomb of mass 2 kg which is at rest explodes into three fragments of equal masses. A stationary bomb explodes into two fragments of masses 0. Kinetic energy is conserved in this process. If kinetic energy of 4Kg piece is 200J. The second fragment of mass m 2 = 3 kg moves at a 45 angle from the horizontal at v 2 = 80 m/s. 1 answer. D P 2 / P 1. Concept: A stationary shell explodes into two fragments, having masses in the ratio of 1: 2. Two of these fragments with mass m1 = 2 kg, and m2 = 1 kg respectively, travel in left direction; the other fragment with mass m3 = 3 kg travels in opposite direction. A 12 kg bomb at rest explodes into two pieces of 4 kg and 8 kg. A. 33. v = √50 m/s. The It suddenly explodes into two fragments of masses 1 g and 3 g. 04:06. 1:2. The total energy imparted to the two fragments is (1) 1. asked Jun 12, 2019 in Physics by PalakAgrawal A stationary shell explodes into two fragments, having masses in the ratio of 1: 2. Find the value of k. Question . So I am not able to understand or get an A body of mass `1kg` initially at rest explodes and breaks into three parts of masses in the ration ` 1: 2: 3. a bomb explodes into two fragments of masses 2kg and 1kg . A stationary bomb explode into two parts of masses 3kg and 1kg. If the 'm' kg piece flies off with a speed of 40 m s A bomb of mass 1 k g, initially at rest, explodes into three fragments having masses in the ratio 1: 1: 3. A stationary body explodes into two fragments of masses m 1 and m 2. of the fr To solve the problem, we need to analyze the motion of the bomb and the subsequent explosion into two fragments. If the bigger fragment has a kinetic energy of 100 J, find the kinetic energy of the smaller fragment: Ans. We need to calculate the velocity of third fragment. A bomb at rest explodes into two fragments of mass 3 kg and 1 kg The total kinetic energy of fragments is 6×10 4 J. of mass 6 kg is: View Solution. A stationary bomb of mass 250 k g suddenly explodes in two fragments in proportion of 1: 4. The velocity of mass `3 kg is 1. And law of conservation of momentum is based on newton's second and third law. C. The magnitude of velocity of third fragment is : A bomb of mass 9 k g explodes into the fragments of masses 3 k g and 6 k g. Find out kinetic energy of 6Kg piece . The total kinetic energy after the explosion is given as $ 2400 \, \text{J} $. A bomb of mass `9 kg` explodes into `2` pieces of mass `3 kg` and `6 kg`. When it breaks into fragments, the momentum must be conserved. The total K. The sum of the kinetic energies of the fragments must be zero. 14 m above the x-axis. The two lighter fragments fly off at right angles to each other with a speed of 15 m / s each. If E 1 and E 2 represent the energies carried by masses m 1 and m 2 respectively, then which of the following is correct? J K CET 2007: A stationary bomb explodes into two parts of masses in the ratio of 1:3 . The smaller fragment moves with a velocity of `6 m//s`. The energy released during the process is, a bomb of 12 k g explodes into two pieces of masses 4 k g s and 8 k g. of the smaller fragment is 216 J. A bomb falling freely bursts after 10 sec. 0 k g. A particle of mass m is made to move with uniform speed v 0 along the perimeter of a regular hexagon. The fragments that move to the right have the same mass m2 and the same speed v2 , one moving at an angle θ=15∘ above the x-axis, and the other moving at the A bomb at rest explodes into three fragments. 8kJ Step by step video & image solution for A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of 9m//s and 12//s Calculate the speed of the third fragment . The position of the heavier A shell of mass `20 kg` at rest explodes into two fragments whose masses are in the ratio `2 : 3`. NEET 2022 Official Paper (Held On: 17 July, 2022) A shell of mass 2 kg and moving at a rate of 4 m/s suddenly explodes into two equal fragments. The total energy imparted to the two fragment is. A bomb of mass 9kg explodes into 2 pieces of mass 3kg and 6kg. The K. A bomb of mass 1 kg initially at rest, explodes and breaks into three fragments of masses in the ratio 1:1:3. Mathematically, it can be written as:m * 0 = m1 * v1 + m2 A bomb is projected with speed 10 m/s at an angle 30 with the horizontal. If E 1 and E 2 represent the energies carried by masses m 1 and m 2 respectively, then which of the following is correct? A stationary bomb explode into two parts of masses 3kg and 1kg. If the smaller mass M flies with velocity 20i +50j, the velocity of larger mass A particle of mass 4m, at rest, explodes into three fragments. A rocket is projected straight up and explodes into three equally massive fragments just as it reaches the top of its flight. 40 kg 0. IF the momentum of these fragments are p 1 and p 2 then what will be the ratio of their kinetic energies? A toy bomb slides on a smooth surface along the x-axis. The velocity of 8 kg mass is 6 m / sec . Let the velocity of m 1 be v m s-1. Submit. The 1 kg and 2 kg pieces fly off with speeds of 12 m s − 1 along the x-axis and 8 m s − 1 along the y-axis respectively. The velocity of the lighter fragment immediately after the explosion is 1) 50ms upward 2) 75ms downward 3) 100ms upward 4) 400ms' upward Laws of A rocket is projected straight up and explodes into three equally massive fragments just as it reaches the top of its flight. The two fragments reach the ground at the s; A 1. If the explosion imparts 48 J of translational kinetic energy to the fragments divided equally, the velocity (magnitude and direction both) of each fragment :- A bomb that is initially at rest explodes into two unequal fragments. If one of the fragments starts moving vertically upwards with velocity v 0, then the other fragment will move: I have read that when a bomb explodes into fragments, then total momentum of the system remains conserved. The smaller mass goes at a speed of 90 m/s. 1200 N This same principle of momentum conservation can be applied to explosions. 5 kg, then its velocity is Click here👆to get an answer to your question ️ A bomb initially at rest explodes by it self into three equal mass fragments. Two fragments fly off at right angles with velocity 12 m / s and 9 m / s. At the maximum height from the ground it explodes into two fragments of equal mass. If the heavier mass moves with a velocity 4 m/s, what is the v A body of mass 1 kg, initially at rest, explodes and breaks into three fragments of masses in the ratio 1: 1: 3. These two fragments: the one with mass 2 kg moves with a speed of 12 m s − 1, and the other one with mass 1 kg moves with [8 m s − 1. View Solution. M (0) = m 1 v 1 + m 2 v 2 m 1 v 1 + m 2 v 2 = 0 m 1 v 1 = − m 2 v 2 A body of mass 1 kg initially at rest explodes and breaks into three fragments of masses in the ratio 1:1:3. Mar. In an explosion, an internal impulse acts in order to propel the parts of a system (often a single object) into a variety of directions. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third (lighter) fragment is: This question was previously asked in. The total KE of the two parts after explosioons is 2400J. 2 kg spring activated bomb slides on a smooth surface along the x-axis with a speed of 0. If the initial velocity of first segments is v 1 = n t 1 + t 2 g (t 2 2 − t 1 2 ) , find n. At the highest point of its path, the projectile explodes and breaks up into two fragments of masses 1 k g and 4 k g. of the smaller fragment A. Now this explodes into two fragments whose masses are in the ratio 2 : 3. The velocity of m 2 is 6 m s-1. the velocity of 8 k g mass is 4 6 m / s. 1. At the time when all fragments reach at ground, the displacement of the center of mass of bomb from initial point will be (g = 10 m s 2) Given weight of the shell is = 20 Kg. 9 m/s along the negative y-axis. The total kinetic energy of the fragment is 6X 10^4 Joule. 40 kg and a speed of 0. It will go upwards with speed `40 m//s` B. 07 kJ(2) 2. if the bigger fragment has a kinetic energy of 100 joule find the kinetic energy of the smaller segment v² = 100/2. )300/5J. It suddenly explodes into two fragments of masses 1 g and 3 g. After the explosion, the individual parts of the system (that is often a collection of fragments from the University of California, San Diego A shell of mass 20 kg at rest explodes into two fragments whose masses are in the ratio 2 : 3. 4 A bomb of mass 9 kg explodes into 2 pieces of mass 3 kg and 6 kg. 3k points) class-11; linear-momentum-&-its-conservation; 0 votes. Each one of them has the same mass. 600 NB. the velocity of mass 3 kg is 15 metre per second. Step by step video, text & image solution for A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of 9m//s and 12//s Calculate the speed of the third fragment . If one fragment comes to rest immediately after explosion, then the horizontal range of centre A bomb of mass 9 k g explodes into the fragments of masses 3 k g and 6 k g. We want to get the kinetic energy for the smaller particle. A bomb at rest explodes into two parts of masses m 1 and m 2. `12ms^(-1)` C. A body of mass 5 kg initially at rest explodes into 3 fragments with mass ratio 3 : 1 : 1. If the momentum of the lighter fragment is ' P, then the energy released in the explosion is 10 km 7 P 2 . When a stationary bomb explodes into two fragments, the total momentum of the system before and after the explosion must be conserved. These two fragments: the one with mass 2 kg moves with a speed of 12 m/s, and the other one with mass 1 kg moves with 8 m/s. Q. If the fragments having equal mass fly off along mutually perpendicular A 12 kg bomb at rest explodes into two pieces of 4 kg and 8 kg. One of the fragments receives a horizontal velocity u. The horizontal distance between the two fragments, when their displacement vectors is inclined at 60 0 relative to each other is (g=10\,m/s^2$ Given:Mass of bomb (m) = 12 kgMass of one piece (m1) = 4 kgMass of the other piece (m2) = 8 kgVelocity of m2 (v2) = 6 m/sWe need to find the kinetic energy of the 4 kg mass (m1). If the momentums of the two parts be P 1 and P 2, then their kinetic energies will be in the ratio of: A m 1 / m 2. of the fragments is 6. The smaller mass goes at a speed of 80 m/s . The smaller mass goes at a speed of 80 ms-1. A bomb of mass 3. 2. 1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep, NEET preparation and CBSE, UP Board, Bihar Board, Rajasthan Board, MP This same principle of momentum conservation can be applied to explosions. The velocity of mass 3kg is 16 m/s . of a moving particle is transferred to station Question: Question 45 1 pts A bomb explodes into two fragments of masses 3. 4 kg and 4 Kg. What is the velocity of the other fragment? O 14 m/s -14 m/s OOO 20 m/s -15 m/s A bomb at rest explodes into three equal fragments. Step 2: Calculating kinetic energy. What will be the magnitude of momentum of third fragment? View Solution. A bomb at rest explodes into a large number of tiny fragments. At high altitude , a body explodes at rest into two equal fragments with one fragment receiving horizontal velocity of `10 m//s`. The total energy imparted to the two fragments is by Physics experts to help you in doubts & scoring excellent marks in Class 11 exams. IF the momentum of these fragments are p 1 and p 2 then what will be the ratio of their kinetic energies? A bomb at rest explodes into three fragments. The total energy imparted to the two fragments is : View Solution. The two pieces of equal mass fly off perpendicular to each other with a speed of 15 ms − 1 each. 0 kg . If momentum of one fragment It explodes into three fragments having mass in the ratio 2: 2: 1. 0 kg`. E) 31°. A 600J. M (0) = m 1 v 1 + m 2 v 2 m 1 v 1 + m 2 v 2 = 0 m 1 v 1 = − m 2 v 2 A stationary particle explodes into two particles of masses m 1 and m 2 which move in opposite direction with velocities v 1 and v 2. )400/3J B. One piece of 2 kgmass moves with a velocity of 8 ms 1 at right angles to the other piece of mass 1 kg moving with a velocity of 12 ms 1. A bomb of mass 9 k g explodes into the fragments of masses 3 k g and 6 k g. A bomb of mass `1 kg` is thrown vertically upwards with a speed of `100m//s`. 2 A bomb of mass 7 m explodes into two fragments of masses 4 m and 3 m. The fragments go in directions inclined with the original line of motion with equal velocities. Q2. At the origin, the bomb explodes into two fragments. At highest point, it explodes into two fragments of equal masses. A bomb initially at rest explodes by it self into three equal mass fragments. If the velocity of the heavier part is v. A bomb at rest explodes into two pieces. 4 kg and 4 kg. A bomb of mass `3. The total energy imparted to t A bomb explodes into three fragments of equal masses. The more massive fragment has more kinetic energy than the less massive fragment. If momentum of one fragment 4. 1kJ 2. If after explosion one fragment retraces its path, then find the velocity of second fragment. We can break down the initial velocity into horizontal and vertical A bomb at rest explodes into two fragments of mass 3 kg and 1 kg The total kinetic energy of fragments is 6×10 4 J. Ans. Two of the fragments each of mass m are found to move with a speed v each in mu. The total momentum of the A bomb at rest explodes onto three fragments . 0 kg and 1. 0k points) A body of mass 1 kg, initially at rest, explodes and breaks into three fragments of masses in the ratio 1:1:3. 001 kg m 2 = 3 g = 3 × 1 Dec 03,2024 - A bomb of mass 3. Immediately after the explosion, the first fragment of mass m 1 = 2 kg travels leftward at speed v 1 = 100 m/s. The velocity of 18 kg mass is 6 m/sec. 1000 J. The total energy released in the explosion is : 2 m v 2; 1 2 m v 2; m v 2; 3 2 m v 2 A stationary body explodes into two fragments of masses m 1 and m 2. The A bomb at rest explodes into two parts of masses m 1 and m 2 If the momentums the two parts be p 1 and p 2 then their kinetic energies will be in the ratio of Q. $\begingroup$ Forget the airplane, take it out into deep space. 5 x10^4 Joule; 205 kg m/s O 1. After the explosion, the individual parts of the system (that is often a collection of fragments from the original object) have momentum. The second fragment of mass m2 = 3 kg moves at a 45 angle from the horizontal at v2 = 80 m/s. Two fragments fly off at right angles to each other with velocities 9 m/s and 12 m/s, respectively. A bomb of mass m = 1 kg thrown vertically upwards with a speed u = 100 m/s explodes into two parts after t = 5 s. 1200J. The second fragment of mass m 2 = A bomb at rest explodes into three fragments of equal masses. Two fragments of mass m each move along a mutually perpendicular direction with speed v In an explosion, an internal impulse acts in order to propel the parts of a system (often a single object) into a variety of directions. Questions A bomb of mass 6 kg initially at rest explodes into two fragments of masses of 4 kg and 2 kg, respectively. 1 s, find out the average force acting on the third particle, if total mass of the bomb is 12 kg. A fragment of mass m 1 = 400 g moves downwards with a speed v 1 = 25 m/s, then speed v 2 and direction of another mass m 2 will be? 40 m/s downwards; 40 m/s upwards; 60 m/s upwards; 100 m/s upwards 2 A bomb of mass 7 m explodes into two fragments of masses 4 m and 3 m. 0 7kJ 2. 4 kJ (4) 4. If the velocities of fragments 1 and 2 are v1 = 5 m/s and v2 = 2 m/s respectively, find the velocity of fragment 3. It explodes into three fragments having mass in the ratio 2: 2: 1. the total K. A bomb at rest explodes into three fragments of equal masses. 8kJ Step by step video, text & image solution for A bomb of mass 3. 80 kg 0. Immediately after the explosion, the first fragment of mass m 1 = 2 k g travels leftward at speed v 1 = 1 0 0 m s. of the system at the highest point is doubled. A bomb of mass 9 kg explodes into 2 pieces of mass 3 kg and 6 kg. B m 2 / m 1. >> A bomb explodes by itself into two fragm. The time interval after which the velocity vectors will be inclined at 120 o to each other is: A bomb at rest at the summit of a cliff breaks into two equal fragments. 50 m / s. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third (lighter) fragment is: A bomb explodes into three fragments having masses in the ratio of 1: 1: 3. Two fragments of mass m each move along a mutually perpendicular direction with speed v each. A bomb explodes in mid-air into two equal fragments. If one fragment comes to rest immediately after explosion, then the horizontal range of centre of mass is found it one fragm then A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of 9 m / s and 12 / s Calculate the speed of the third fragment . The third fragment of mass m 3 = 4 k g moves at an angle of 3 0 I have read that when a bomb explodes into fragments, then total momentum of the system remains conserved. Right after the explosion what can we say about their kinetic energy? Assume all other forces are very small as compared with the internal forces of the explosion. Here's a step-by-step solution: Step 1: Determine the initial conditions of the bomb The bomb is projected with an initial speed $ v $ at an angle $ \theta $ with the horizontal. The second fragment, of mass m2 = 3. A bomb explodes into three fragments. A stationary bomb explodes into three pieces. of the gragments is 6. The second fragment of mass m 2 = 3 k g moves at a 4 5 ° angle from the horizontal at v 2 = 8 0 m s. 0Kg explodes in air into two pieces of masses 2. 5 x10^4 A bomb of mass 3 kg at rest, explodes in air into two pieces of masses 2 kg and 1 kg. A bomb of mass 2 kg which is at rest explodes into three fragments of equal masses. `15ms^(-1)` D. Solution For A bomb is kept stationary at a point. The second moves at 31 m/s. The horizontal distance between the two fragments, when their displacement vectors is inclined at 60 0 relative to each other is (g=10\,m/s^2$ Solution For A bomb of mass 12 kg at rest explodes into two fragments of masses in the ratio 1: 3. a stationary bomb explodes into two fragments of mass 0. A shell of mass m is at rest initially. A projectile in flight explodes into several fragments. 4 kg and a spe A bomb at rest explodes into three fragments. Let m 1 , m 2 be the masses of first and second fragments respectively and v 1 , v 2 be their velocities after explosion From conservation of momentum M v = m 1 , v 1 + m 2 v 2 Where, M is mass of bomb before explosion and v is the velocity Since, bomb is stationary, hence v = 0 Given, m 1 = 1 g = 1 × 1 0 − 3 kg = 0. What will happen to the second fragment just after the explosion ? `(g=10ms^(-1))` A. A bomb at rest explodes onto three fragments . View Solution At the highest point, the shell explodes into two fragments having masses in the ration 1: 3, with each fragment moving horizontally immediately after the explosion. 37 (A)2 +21 (C)-2 +2] (B)2 1 -2; (D) -21 -2] A . The total energy imparted to the two fragments is A bomb at rest explodes into two parts of masses m 1 and m 2. The velocity of mass 3 kg is 1. It explodes into three fragments having mass in the ratio 2 ∶ 2 ∶ 1. A bomb of mass 1 kg initially at rest, explodes and breaks into three fragments of masses in the ratio 1: 1: 3. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third (lighter a stationary bomb explodes into two fragments of mass 0. The magnitude of relative velocity between the two fragments after explosion is 2E(m + m2) (1) V (mm) mm2 (2) 2E (m + m) (3) V2E Vma + Vmza 1 mm A bomb of mass m explodes into two pieces. Two fragments fly off at right angles to each other with velocities 9 m s − 1 and 12 m s − 1 respectively. Immediately after the explosion, the first fragment of mass m1 = 2 kg travels leftward at speed v1 = 100 m/s. Solution: Conservation of Momentum: When a bomb explodes, the total momentum of the system before the explosion is equal to the total momentum of the system after the explosion. a bomb of mass 3 kg at rest explodes into two parts one part of mass 2 kg is found at a speed of 12 metre per second towards the east what is the velocity of the other part. 1800J. 34 \times 10^{-27} kg is initially at rest. E. Using conservation of momentum A bomb of mass 3. 5 x10^4 Joule: 300 kg m/s O 4. the kinetic energy of the other mass is View Solution Q 4 A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of `9m//s` and `12// asked Jul 7, 2019 in Physics by RakheeChawla (74. A bomb of mass 3 kg at rest, explodes in air into two pieces of masses 2 kg and 1 kg. Step 2: Define the Momentum of the Fragments Let’s denote the momentum of the two fragments as $ P1 $ and $ P2 $, where both have a magnitude of $ P $ and are moving at an angle of $ 60^\circ $ to each other. The heavier fragment attains a Kinetic energy of 100 J. 0 votes . suddenly explodes into two fragments of mass 1/8 kg and 7/8 kg. 0 \\mathrm{~kg} \\). If the bigger fragment has a kinetic energy of 100 J, find the kinetic energy of the smaller fragment. If the explosion process occurs in 0. the total energy imparted to the two fragments is 1. The two pieces of equal masses fly off perpendicular to each other with a speed 15 A bomb at rest explodes into three fragments of equal masses. In the figure, the angle 0, made by the velocity vector of fragment 2 and the x-axis, is closest to y' 2 0. 40 kg and a spe; An object, initially at rest, explodes into three fragments, which fly apart along a frictionless surface (x-y plane). Their velocities, masses, and directions are as shown. 4 kJ 4. A bomb of mass m is projected from the ground with speed v at angle with the horizontal. What When a stationary bomb explodes into two fragments, the total momentum of the system before and after the explosion must be conserved. If the momentums of the two parts be P 1 and P 2, then their kinetic energies will be in the ratio of At the maximum height from the ground it explodes into two fragments of equal mass. Explode the bomb in the absence of air or, of any nearby object. Find the speed of the heavier fragment. First, we need to find the velocity of each fragment after the explosion. AUS. A bomb of mass 9 kg explodes into two pieces of mass 3kg and 6kg . A bomb of mass 4 kg explodes in air into two pieces of masses 3 kg and 1 kg. A bom of mass `1 kg` is thrown vertically upwards with a speed of `100m//s`. Since the bomb was initially stationary, its initial momentum was zero. If the lighter fragment falls at a distance R from the point of projection, behind the point of projection, the distance at which the order fragments falls from the point of Instead, it explodes into two fragments of equal mass, one of which lands 100m beyond the target. 0 × 10 4 j o u l e, then calculate the momentum of smaller fragment (in kg-m/s). If one fragment comes to rest immediately after explosion, then the horizontal range of centre A bomb explodes in mid air into two equal fragments . The energy of explosion is equal to: View Solution. An object of mass 5 k g is projected with a velocity of 2 0 m s − 1 at an angle of 6 0 ∘ to the horizontal. If momentum of one fragments p, the minimum energy of explosion is. A bomb of mass 30 kg at rest explodes into two pieces of masses 18 kg and 12 kg. One of the fragments is observed to come straight down in a time t, while the other two land at a time t 2, after the burst. Velocity and acceleration of a particle are v = (2 Step by step video, text & image solution for A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of 9m//s and 12//s Calculate the speed of the third fragment . What is the K. Calculate (i) , kinetic energy of the bigger fragment (ii) momentum of the smaller fragment. 0k points) A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of 9 m / s and 12 / s Calculate the speed of the third fragment . A bomb at rest explodes into two fragments of masses \\( 3. A bomb is kept stationary at a point. A bomb at rest explodes into two fragments of masses 3. 0 kg` and `1. If the mass of the third piece is 0. asked Jun 7, 2020 in Physics by Navinsingh (86. 4xx10^(4)J`. CONCEPT: The product of mass and velocity is A bomb of mass 30 kg at rest explodes into two pieces of masses 18 kg and 12 kg. The velocity of mass 3kg is 1. Two fragments fly off at right angles to each other with velocities of \\( 5 \\mathrm{~ms}^{-1} \\ A bomb initially at rest explodes by it self into three equal mass fragments. `18ms^(-1)` class-11; A body of mass 1 kg, initially at rest, explodes and breaks into three fragments of masses in the ratio 1: 1: 3. Let the mass of bomb be M and mass of two pieces be m 1 and m 2 respectively. A shell of mass `20 kg` at rest explodes into two fragments whose masses are in the ratio `2 : 3`. And law of conservation of momentum is based on newton's A particle of mass 5 m at rest suddenly breaks on its own into three fragments. The velocity of mass 3 k g is 16 m s View Solution. 0 Kg explodes in air into two pieces of masses 2. Calculate the speed A shell of mass m is at rest initially. An instant later, the smaller fragment is 0. [4] For this bomb you take tung oil, yin hsiu, salammoniac, chin chih, scallion juice, and heat them so as to coat a lot of iron pellets and bits of broken porcelain. 0 kg explodes in air into two pieces of masses 2. 0kg and 1. The total momentum of all the fragments. 9k points) To solve the problem step by step, we will use the principles of conservation of momentum and kinetic energy. The third fragment of mass m 3 = 4 kg moves at an angle of 30 below the horizontal with velocity v 3 = 50 m/s. 0 \\mathrm{~kg} \\) and \\( 1. Which one of the following statements concerning this event is true? A. After 5 seconds, it explodes into two fragments. Two fragments fly off at right angles to each other with velocity 9 m/s and 12 m/s. A neutron (mass 1. `3. The conservation of momentum states that the total momentum before the explosion is equal to the total momentum after the explosion. The smaller mass goes at a speed of 80 m/s. 535 views. A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3 Click here👆to get an answer to your question ️ 165 ) A bomb at rest explodes into three fragments! ) X Y and Z. One fragment of mass `400 gm` is found to go down with a speed of `25m//s`. Calculate the speed of the third fragment. The momentum of the two parts are $$4\hat{i . The third fragment, of mass m3 = 4. The kinetic energy of the The mass of both the pieces of the bomb are m 1 = 4 k g and m 2 = 8 k g respectively. A stationary bomb explodes into two fragments of masses m 1 and m 2. If the velocity of the heavier fragment is 1 0 x , determine x. The velocities of two fragments are (3 ∧i + 2 ∧j ) m/s and ( - ∧i - 4 ∧j ) m/s. The smaller fragment moves with a velocity of 6 ms -1. 9k points) class-11; laws-of-motion; friction; 0 votes. Immediately after the explosion, the first fragment, of mass m1= 2. We can use the conservation of momentum principle, which states that the total momentum of a system before and after an event remains constant, as long as there are no external forces acting Show more Doubtnut is No. If the momentum of these fragments are p 1 and p 2, then what will be the ratio of their kinetic energies? Open in App. `9ms^(-1)` B. The total energy imparted to the two fragments is Both fragment will possess the equal linear momentum m1v1=m2v2⇒1×80=2×v2⇒v2=40 m . The total energy imparted to the two fragments is The total energy imparted to the two fragments is A bomb explodes into three fragments. The first, of mass 17 g, moves in the positive x direction at 38 m/s. If momentum of one fragment At high altitude , a body explodes at rest into two equal fragments with one fragment receiving horizontal velocity of `10 m//s`. The third fragment will move with a speed : 18. Step 1: Understand the problem We have a bomb that explodes into two parts with masses $ m1 = 1 \, \text{kg} $ and $ m2 = 3 \, \text{kg} $. The total kinetic energy of the fragments is 6 × 10 4 J . What is the angle between their directions of motion ? Class: 11Subject: PHYSICSChapter: LAWS OF MOTION Questions A bomb of mass 6 kg initially at rest explodes into two fragments of masses of 4 kg and 2 kg, respectively. The velocities of two fragments are (3 i +21) m/s and (-i-4J)m's. After 5 seconds, it explodes into two A toy bomb slides on a smooth surface along the x-axis. 67 x 10-27 kol marine at A bomb explodes into three fragments. It suddenly explodes into two fragments of masses \$ 1 \\mathrm{~g} \$ and \$ 3 \\mathrm{~g} \$. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. 2-kg spring-activated toy bomb slides on a smooth surface along the x-axis with a speed of 0. C 1200J. Calculate kinetic energy of bigger fragment. The smaller fragment moves with a velocity of `6 m/ asked Jun 12, 2019 in Physics by PalakAgrawal (76. 18, 2022 05:51 p. Therefore, the momentum of the two fragments must be equal and opposite after the explosion to conserve momentum. 0 k g and 1. The KE of the smaller part is. A bomb explodes by itself into two fragments of masses 3 k g and 1 k g. This is known as the conservation of momentum. The heavier fragment attains a Kinetic energy of 100 J. These two fragments: asked May 8, 2020 in Laws of Motion by Ravi01 (49. If the total energy of both the fragments is 6. Open in App. The third fragment of mass m3 = 4 kg moves at an angle of 30 below the horizontal with velocity v3 = 50 m/s. B 1800J. It suddenly explodes into two fragments of masses 1g and 3g. 7k points) closed Nov 1, 2021 by Navinsingh. b. 0kg. 5 x10^4 A 1. Step 3: Calculate the Resultant Momentum of the First Two At high altitude , a body explodes at rest into two equal fragments with one fragment receiving horizontal velocity of `10 m//s`. A bomb at rest explodes into three fragments of equal massses Two fragments fly off at right angles to each other with velocities of `9m//s` and `12//s` Calculate the speed of the third fragment . The velocity of the third fragment is (in m/s) - 0. The speed of the third fragment is A bomb at rest explodes into three fragments of equal masses. A bomb of mass M at rest; some how on its own explodes into three fragments having masses in ratio of asked Nov 3, 2022 in Physics by Ankurgupta ( 51. B. 8 kJ? - EduRev NEET Question is disucussed on EduRev Study Group by 510 NEET Students. C P 1 / P 2. The velocity of heavier fragment immediately after the explosion is 200 ms vertically downwards. Two fragments fly off at right angles with velocity 12 m/s and 9 m/s. a. A stationary object explodes into masses m 1 and m 2. A bomb of mass M at rest explodes into two fragments of masses m 1 and m 2. The Kinetic energy released in the explosion is: To solve the problem of finding the ratio of the kinetic energies of two parts of a bomb that explodes into two masses m 1 and m 2 , we can follow these steps: Step 1: Understand the Initial Conditions The bomb is at rest before the explosion. An object of mass $$3kg$$ at rest in space suddenly explodes into three parts of same mass. `18ms^(-1)` class-11; At the origin 0, the bomb explodes into two fragments. Two fragments fly off at right angles to each other. Total momentum before explosion = Total momentum after explosionP(before) = P(after) Calculation of Total Momentum Before Explosion: Before Once the bomb explodes, the resulting fragments are capable of piercing the skin and blinding enemy soldiers. IF the momentum of these fragments are p 1 and p 2 then what will be the ratio of their kinetic energies? View Solution. Two of fragments each of mass 'm' are found to move with a speed 60 m/s in mutually perpendicular directions. Q5. Fragment 1 has a mass of 0. The two pieces of equal mass fly off perpendicular to each other with a speed of 30 m/sec each. The magnitude of velocity of third fragment is : Question: Question 45 1 pts A bomb explodes into two fragments of masses 3. The total kinetic energy of the fragments is \\( 6 \\ti -32 A bomb initially at rest explodes by itself into three equal mass fragments. 90 m/s Before After A) 599 B) 38°. V2 + Um A shell moving through the air is split into two fragments of masses m, and m, by its explosion which adds on energy E to the fragments. The velocities of two fragments are (3 i +2 )m/s and (- i -4ſ)m/s. Velocity of second fragment = (-i-4j) m/s. A spherical shell at rest at the origin explodes into three fragments of masses 1 kg, 2 kg and 'm' kg. C) 37° D) 53°. of mass 6kg is. The kinetic energy of the other mass is. 6 m//s`. 5xx10^(4)J` A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg . The two fragments have linear momentum as $$-3p\hat{i}$$ and $$2p\hat{j}$$. If the velocity of the heavier fragment is 10 √ x, determine x. Calculate the angle {eq}\theta {/eq}. A fragment of mass m 1 = 400 g moves downwards with a speed v 1 = 25 m/s, then speed v 2 and direction of another mass m 2 will be? 40 m/s downwards; 40 m/s upwards; 60 m/s upwards; 100 m/s upwards Ans. 84 J` A particle of mass 4 m which is at rest explodes into three fragments. A bomb at rest explodes into three equal fragments. 4×104J. A bomb explodes into three fragments of equal masses. By momentum conservation. A uranium 238 nucleus, initially at rest emits an alpha particle with 02:55. 2. After 5 seconds, it explodes into two parts. 0 kg, travels leftward at v1 = 100 (meters per second). `2. What is the relation between the direction of their motion? asked Feb 2, 2021 in Physics by Daakshya ( 26. 0 kg. Which of the following correctly! deseribes the motion of the fragments? VLX They fly in A bomb at rest explodes into two fragments of mass 3 kg and 1 kg The total kinetic energy of fragments is 6×10 4 J. In the mid-air bomb explodes in different fragments and they all move in different directions. If the momentum of 4 kg piece is 20 Ns, the kinetic energy of the A bomb explodes into three fragments. kcigtsxp bxznq xuusm nwnt zoxun rmu sipz aqsld vjuql fjvlszx